Files
TypeScript/tests
Andy a86882f996 If parsing a function type fails, parseTypeReference() to ensure something is returned (#24567) (#24695)
* If parsing a function type fails, parseTypeReference() to ensure something is returned

* Avoid tryParse

* Add missing semicolon

* Don't check for undefined, check for missing type

* Don't set parameters undefined, set to missingList and return false

* Update API baselines

* Code review
2018-06-05 11:02:58 -07:00
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